1 )
What is total number of radical and angular nodes present in 5f orbital ?
Solution
: -
Radical
and angular nodes : -
Region where electron density in an orbital is zero .
5f
orbital : -
Principal quantum number is number of shells . So , n = 5
.
Azimuthal quantum number is number of sub shells . So , L
= 3 .
∴ Azimuthal quantum number for different sub shells : -
s = 0 , p = 1
, d = 2 , f =
3 .
So , now we can find radical and angular nodes : -
Radical
nodes : - n – L – 1 = 5 –
3 – 1 =
1 .
Angular
nodes : - L = 3 .
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2 )
The number of nodes for 4f orbital is : -
A ) 3 , B
) 4 ,
C ) 6 , D
) None of these ,
Correct
Answer : - A ) 3 ,
Solution
: -
For 4f : - n =
4 ,
L = 3 .
So , number of angular nodes =
L = 3 .
Number of radial nodes
= n – L – 1 = 4 –
3 -1 =
0 .
So , total number of nodes = 3 +
0 = 3
, Answer .
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3 )
Find the magnetic moment of a divalent ion in aqueous solution , if its atomic
number is 25 ?
A ) 1 BM , B
) 5.9 BM ,
C ) 17 BM , D
) None of these ,
Correct
Answer : - B ) 5.9 BM ,
Solution : -
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4 )
How many spherical nodes are present in 4s orbital in a hydrogen atom ?
A ) 1 , B
) 2 ,
C ) 3 , D
) None of these ,
Correct
Answer : - C ) 3 ,
Solution
: -
So , Spherical nodes
= n – L – 1 ,
∴ For 4s
: - n = 4 and L
= 0 ,
So , Spherical nodes
= 4 – 0 – 1 = 3 nodes ,
Answer .
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